Bonjours Pouvez vous m'aider pour ces 3 calcul avec étape svp [tex] {( - 4)}^{3} - 2 \times {(3}^{2} - {2}^{3} ) {}^{4} [/tex] [tex] {5}^{ - 2} - 2 \times

Réponse :

bonsoir,

(-4)³ - 2×(3² - 2³)⁴

= -64 - 2× ( 9 - 8)⁴

= -64 - 2×1⁴

= -64 - 2

= -66

5⁻² - 2 × ( 3² + 1⁵ ) ⁻³

= 1/5² - 2 × ( 9 + 1 )  ⁻³

= 1/25 - 2× 10 ⁻³

= 1/25 - 2 × 1/10³

= 1/25 - 2/10³

= 1/25 - 2/1000

= 1×20/25×20 - 2÷2/1000÷2

= 20/500 - 1/500

= 19/500

4⁻³ + 6⁻³ + 12⁻¹

= 1/4³ + 1/6³ + 1/12¹

=1/64 + 1/216 + 1/12

= 179/1728

voila :)

(-4)^3-2×(3^2-2^3)^4

=-64-2×(9-8)^4

=-64-2×(+1)^4

=-64-2×1

=-64-2

=-66

5^-2-2×(3^2+1^5)^(-3)

=1/5^2-2×(9+1)^(-3)

=1/25-2×(+10)^(-3)

=0,04-2×1/10^3

=0,04-2×0,001

=0,04-0,002

=0,038

4^-3+6^-3+12^-1

=1/4^3+1/6^3+1/12^1

=1/64+1/216+1/12

=(27+8+144)/1728

=179/1728