Mathématiques

Question

Bonjour , pouvez vous m’aidez ?



résultat sous la forme d'une fraction irréductible

B = 1 + (8/8 + 3/4 - 1/12)/(5/6 + 1/3 + 2);

A = 2 + 8/(9 + 5/19);


C = (5/12)/(7/3 * 8/15 - 5/6)

1 Réponse

  • Bonjour

    Résultat sous la forme d'une fraction irréductible

    B = 1 + (8/8 + 3/4 - 1/12)/(5/6 + 1/3 + 2)

    B = 1 + [(8 x 3) / (8 x 3) + (3 x 6) / (4 x 6) - (1 x 2) / (12 x 2) : [5/6 + (1 x 2) / (3 x 2) + (2 x 6) / (1 x 6)]

    B = 1 + (24/24 + 18/24 - 2/24)  :(5/6 + 2/6 + 12/6)

    B = 1 + 40/24 : 19/6

    B = 1 + 40/24 x 6/19

    B = 1 + 240/456

    B = (1 x 19) / (1 x 19) + (24 x 10) / (24 x 19)

    B = 19/19 + 10/19

    B = 29/19

    A = 2 + 8/(9 + 5/19)

    A = 2 + 8 : [(9 x 19) / (1 x 19) + 5/19]

    A = 2 + 8 : (171/19 + 5/19)

    A = 2 + 8 : 176/19

    A = 2 + 8 x 19/176

    A = (2 x 176) / (1 x 176) + 152/176

    A = 352/176 + 152/176

    A = 504/176

    A = (8 x 63) / (8 x 22)

    A = 63/22.

    C = (5/12)/(7/3 * 8/15 - 5/6)

    C = 5/12 : (56/45 - 5/6)

    C = 5/12 : [(56 x 2) / (45 x 2) - (5 x 15) / (6 x 15)]

    C = 5/12 : (112/90 - 75/90)

    C = 5/12 : 37/90

    C = 5/12 x 90/37

    C = 450/444

    C = (6 x 75) / (6 x 74)

    C = 75/74.

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